Solution:
Applying KIrchoff's Law for the Lower Loop going counterclockwise starting at Node "a" we obtain,
- 45 + 0.5*I3 + 1.5*I3 + I1*6.0 = 0
Or, 45 - 0.5*I3 - 1.5*I3 - 6*I1 = 0
----Which is matching with optionB .
QUE RE 150 050 45V Which equation best describes the voltage loop equation for the LOWER loop going counterclockwise starting at node 'a: 45 -0.513 +1.513 = 0 O-2.512-18V +0.51, +611 = 0 45 -0.513 +1.513 - 611 = 0 45 -0.51,-1.513 – 671 = 0 Type here to search o E D.
There is a 4nC located at the position (2m,0) and a -6nC charge located at (0,3m). What is the electric potential V at the origin? Ov = (9:10") (1z10 9 (9x10°) (6:10) 2 + = 18 + 18 = 36J/G 3 (9410') (4x 10) (9210) (-6310) V + = 18 - 18 = 0J/C 2 3 ov (9x10") (4x 10") 22 (9x10°) (-6210) + = 9-6=3J/C You can not add them because one is from the x-axis and the other...
omalle 0.52 RE 2.50 ş a 14 R w 6.00 = R 1.50 0.50 245V Which equation best describes the Junction equation for currents at the node 'a O 12 = 1 + 13 13 = 12 + I 12 + I3 = 11 Next Page Page 5 of Lina, quite concerned about her nose, is looking into a concave mirror with a focal length of 40 cm. Determine the image height of the 3.0cm nose when placed 20 cm...
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