Question

Activity: Kirchhoff's Rules Grade (0-6) NAME (print) (sign) Kirchoff's loop rule: the sum of the voltage drops around any loop is , 18V zero. Kirchoff's junction rule: the sum of the currents into any junction (node) is zero. 0.52 There are three loops: the top loop (abcdea), the bottom loop (aefgha), and the outside loop (abcdefgha). 2.5 6.012 Top Loop: Write down Kirchhoff's loop rule for the top loop going clockwise from point a. Use symbols not numbers. Careful of signs! (Remember going through a resistor with the current gives a voltage drop or - Sign: against the current gives a + sign. Going forward through a battery gives a + sign, backwards a-sign.) 0.52 E, -45 V Bottom Loop: Now go clockwise around the bottom loop starting again a point a. Symbols not numbers. Junction a: Finally, write down Kirchhoffs junction rule for the junction at point a. Solution: You now have three equations in the three unknowns Island Is. The solution is simple algebra. You should do it on the back and put the answers here: In approaching Kirchhoff's rules problem, you will need to choose and mark current labels and directions for yourself. The choice is arbitrary, but should be logical. Similarly, the choice of loops and directions (clockwise or counterclockwise) is arbitrary but important since it determines the sign of each term in the equation. You need to do two of the three possible loops. The third is just a linear combination of the other two. You need only one of the two possible junctions

Answer 1

- 18V At point a Titan 10-512 2.51s At point a = 1, +3, - from top loop 18 = 3 Iz +65 – from bottom loop ന്ന {1.562 0.52 45= 2 Iz +6 I 45v from from 45=2(3, -IZ) +6 I 45= 81-212 ② and ③ 18= 3 I₂ +62 82 45=-2 I₂ +81 83 I = 4.75A from € 18= 3 Iz +6+4.75 I= -3.5A 13 = 4.15+3.5 = 8.25A from 0 Scanned with CamScanner