Question

Part 3: RL Circuits: Purpose: Observe the transient current response in an RL circuit. Directions: Using Multisim Live circuit simulator, build an RL (resistor-inductor) series circuit with time constant 5 ms. Use a 5H inductor. You'll have to calculate first the value of the resistor. Using the 'clock voltage' source (this is essentially a square wave function generator), apply an alternating voltage to the RL series components. Set the frequency for the clock voltage source in the following way: First, using the 5ms time constant, consider that you'll want enough time to see the current rise to it's final steady value, and subsequently fall to essentially OA. This means that you'll need ~10 time constants for the current to rise, and another -10 times constants for the current to fall. Find the frequency whose period will correspond to -20 time constants. You can leave the voltage as 5V. Measure only the transient current response of this circuit. You can essentially follow the same steps to measure the transient current as you have previously done with the RC circuit.

it is on a free website, i am just confused on how to build the circuit

Answer 1

,

L 00 time constant for RL cincuit cin is T = L Voltage pulse 7oir .:20sms, L=5H T-sxlots SH R= 5x1035 R- loira T 10ooe