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RLC transients Build the circuit shown in Fig 4. The source is a square wave that switches between 0 and 10 V with a frequenc do not need to build the circuit, just solve the question 1,2 and 3
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from previous 61-2) of 2=0, using 280A = Ri+R2 2x8x 106 - 33a 37.5 38 x 10 3 8 11x37.5 X10% = ex 186 0.206 S Since 841, it isoil venal - Vainal (1- etlec) ota -ottet = 1-0.1 Take m on tolh side tthee = 10.105 Z = Rc (0.105) for 0.9 Vfinal amelarly shSwostitating in a we get 2x8x10 - (3.3 + 0.33) x16 37.5 30X1o7 37.5 2 8 got = 3.63 x 16 39 8= 3.63 x 32.5 - 30 a 8= 2.26 SniVol) = Yoc (Rithe) +SL + Yst H() = - scffy thy ) + c+I HO (RtRg) + ²+ ye comparing with stol aan $+ zowel twă = (Butka)ęte+DATE: 1:01:TID So From fig. we get R R2 pan 3302 23 ZomH 47nt Į Vc mau draw arcuit domain, we can R2 e so if we take transfer

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