Question

QUESTION How would the image height be affected if the ball and observer were immersed in water? It would be smaller. It would be larger There would be no change. PRACTICE IT Use the worked example above to help you solve this problem. A coin 1.95 cm in diameter is imbedded in a solid glass ball of radius r = 30.7 cm (see figure). The index of refraction of the ball is 1.50, and the coin is d = 20.5 cm from the surface. (a) Find the position of the image of the coin. cm (b) Find the height of the coin's image. cm EXERCISE HINTS: GETTING STARTED I'M STUCK! A coin is embedded 20.5 cm from the surface of a similar ball of transparent substance having radius 30.7 cm and unknown composition. The coin's image is virtual and located 15.4 cm from the surface. (a) Find the index of refraction of the substance. (b) Find the magnification M=

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Answer 1

SOLO Poractice it De = 1,95cm R =-30.7cm Given Data . na 1.50 U= d = 20.5cm n=1 Portal the relation Using n, tha A : (12-0) v R 1.50 + I- 2015 V I-1150 -30.7 vc-1758 cm 17.58 cm Honce the position of the Image from Surface Part (by As know Magnification (on) M = chir = -115*17.58 H₂U 1x 2015 mol.286 Ha Ho {Ho=De=1.95} H= 1.286X 1.95 Height of Coins image (H = 2.51cm