Question

Use the worked example above to help you solve this problem. An object 3.15 cm high is placed 20.3 cm from a convex mirror with a focal length of 8.30 cm. (a) Find the position of the image. cm (b) Find the magnification of the mirror. (c) Find the height of the image. cm EXERCISE HINTS: GETTING STARTED I I'M STUCK! Suppose the object is moved so it is 4.15 cm from the same mirror. Repeat parts (a) through (c). (a) 4 = cm (b) M= (c) = cm The image is -Select-

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Answer 1

Solution: we <t we - ) 20.3 Pant I: h=3.15 cm u=20.3 cm (8) f=-8.30 cm know that mirror formula ft te į =) t=25 - 4 201 -8.3 20.3 V = -5.89 cm (6) know that magnification -5.89 m= - = (ES - 0.2gol (1) height of image.h'= mxho ->n'a 0.913cm Part 2 ( Exercise). (9) 4.15 f = -8.3cm, h=3thm qoe image distance, q=-(8.3X4.15 8:3+4'15 q=-2.76 cm 2.76 4.15 (c) h'= 0.666 x 3.15-2.10 cm image is vintial. u = (b) m mo (2 97 -0.666