Question

please answer step by step with correct sig figs and units:

You have 12.0 mol of a diatomic ideal gas at 300 K, and 4.00 kJ of heat to add to it. You can choose to heat it isochorically or isobarically. Which of these two methods will result in a higher final temperature, and what will that final temperature be in Kelvin?

Answer 1

Using the equation of molar heat to find the final temperature of the given processes accordingly.

In Isobaric process , final temperature is higher.

Ans: o n CVAT For Isochoric Process) 4x10² lax 5 R (300-T) १ 4X2X1000 300 - T 6ox 8.31 Ti = 300 - 16.04 283.96 K TE n CpOT flow Isobaric Process 4000 lax ZXR ( 300- 4000 12 300 Ig 84 x 8.31 Ta = 300-11.46 Ta = 888.54 K Higher Temperature is 288.54 6.