Question

GOAL Calculate properties of a convex mirror. PROBLEM An object 3.00 cm high is placed 20.0 cm from a convex mirror with a focal length of magnitude 8.00 cm. Find (a) the position of the image, (b) the magnification of the mirror, and (c) the height of the image STRATEGY This problem again requires only substitution into the mirror and magnification equations. Multiplying the object height by the magnification gives the image height. (A) Find the position of the image. Because the mirror is length is negative, Subsbitute into the 20.0m Solve for g -5.71 cm (B) Find the magnification of the mirror Substitube into the magnification equarion 5.71 em 20.0 m 82 (C) Find the height of the image Multiply the object height by the AM (3.00(o 286) 0458 cm LEARN MORE REMARKS The negative value of q indicates the image is virtual, or behind the mirror. The image is upright because M is positive QUESTION Is the image that a convex mirror produces real or virtual? O The image is always vitual O tt depends on the distance to the object O The image is always real O it depends on the focal length of the mirror Use the worked example above to help you solve this problem. An object 2.56 cm high is placed 20.4 cm from a convex mirror with a focal length of 7.90 cm. (a) Find the position of the image. -5.595x cm

Answer 1

Excersice :

f = 7.90 cm
p = 3.95 cm

a) use, 1/p + 1/q = 1/f

1/q = 1/f - 1/p

1/q = 1/7.9 - 1/3.95

q = -7.90 cm <<<<<<<<--------------Answer

b) M = -q/p

= -(-7.9)/3.95

= 2.00 <<<<<<<<--------------Answer

c) h' = m*h

= 2*2.56

= 5.12 cm <<<<<<<<--------------Answer

The image is virtual and upright