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In a physics experiment, two carts of mass 1.5 kg each are rolled towards each other. The orange cart has a velocity of 2 m/s
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Answer #1

This is a problem of momentum conservation. So the linear momentum before the collision and the linear momentum after the collsion should be equal, that is to say, that the momentum of the whole system is conserved.

Therefore, p_{\text{initial}} = p_{\text{final}}. One does not need the vector sign here, since the above problem is purely one dimensional in nature.

The intial momentum is, p_{\text{initial}} = m_1 v_1 + m_2 v_2 = \frac32 \cdot 2 - \frac32 \cdot 1 ~ m^2/s = \frac32 ~ m^2/s.

And the final momentum is, p_{\text{final}} = m_{\text{final}} v_f = (m_1 + m_2) \cdot v_f = 2 \cdot \frac32 \cdot v_f = 3 \cdot v_f.

Since the initial and the final momentum must be conserved, so equating, p_{\text{initial}} = p_{\text{final}}. One gets on solving for v_f, v_f = \frac12 ~ m/s.

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Answer #2

vf=3-1.5/3=2.5m/s

2.5m/s

source: i am a teacher
answered by: anonymous
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