Question

Two 3 nC and -5 nC electrical charges are located at the base of an equilateral triangle (1 m side). Calculate the total electric potential

in the center (point P) of the triangle.

Dos cargas eléctricas de 3 nC y-5 nC están ubicadas en la base de un triángulo equilátero ( de 1 m de lado). Calcular el potencial eléctrico total en el centro (punto P) del triángulo. 1 m 1 m 1 m

Answer 1

So electric potential due to two charges at the centre is

$V=\frac{kq_1}{r_1}+\frac{kq_2}{r_2}$

Now

$r_1=(\frac{1}{2}m)sec30=\frac{1}{\sqrt3}m$

and same is r2 from negative charge

$r_2=(\frac{1}{2}m)sec30=\frac{1}{\sqrt3}m$

so plug in this we get

$V=\frac{9\times 10^{9}\times 3\times 10^{-9}}{1/\sqrt3}-\frac{9\times 10^{9}\times 5\times 10^{-9}}{1/\sqrt3}$

$V=-31.18V/m$