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Part A A welder using a tank of volume 7.60x10-2 m fills it with oxygen (with a molar mass of 32.0 g/mol) at a gauge pressure

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Answer #1

Ginen data; P. = 2.90x105 pa (gauge). absolute Pi=10125+ 290000 = 391325 pa. V= 7.60 x 102m3 Ti-38.6 c = 31.6k. R for oxygen

Now Final Pressure 1060x10° pa (gauge) i absolute Pressure 101325 + 160000 Pa - 261328 Pa. V= 7.60x102 me Tea 23.7°c 296.7 kanswer for part -(A) = 0.3673 kg

Part (B) = 0.1096 kg

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