Question

Part A A flask with a volume of 2.50 L , provided with a stopcock, contains ethane gas (C2H6) at a temperature of 285 K and atmospheric pressure 1.013x105 Pa . The molar mass of ethane is 30.1 g/mol. The system is warmed to a temperature of 380 K , with the stopcock open to the atmosphere. The stopcock is then closed, and the flask cooled to its original temperature. What is the final pressure of the ethane in the flask? Express your answer in pascals. ΤΕΙ ΑΣΦ ? P2 = Pa Submit Request Answer

Answer 1

low: solume- Partay from ideal gas PV = nRT whene, in= number of moles R= universal gas constant R.=:8.315 Ji molk -3 Number of moles, ni in cold flask n = PVA 1.013X10. Pa X2050X10 mg RT 8.315met: k* 285* → n = 0.1068 mol also number of molesny in the hot + flask is R. Tz . 8.315 /mokk n =P Vi 1,013X105 Pax 250x10mm 8.315 Imolak * 380K → 72 0.0802 moli final pressure of the ethane Now, in the flask Pz = n2 RTY 000802 X8.315x285 = vi 2.50 %10-3 = 0.7602 Xlos P. 2 Pa π

Part BY mass Moss is mo na ME = 0.0802 X 30.1 m 2.414 g g