here,
initial volume of glass , V1 = 1000.42 cm^3
the initial volume of mercury , V2 = 1000.42 cm^3
when change in temperature , dT = 55.6 degree
the coefficient of volume expansion for mercury , beta2 = 18 * 10^-5 K^-1
let the coefficient of volume expansion for glass be beta1
the overflow volume , dV = dV2 - dV1
dV = V2 * beta2 * dT - V1 * beta1 * dT
8.68 = 1000.42 * 55.6 * ( 18 * 10^-5 - beta1)
solving for beta1
beta1 = 2.4 * 10^-5
the coefficient of volume expansion for glass is 2.4 * 10^-5 K^-1
A glass flask whose volume is 1000.42 cm° at 0.0° C is completely filled with mercury...
A glass flask whose volume is 1000.42 cm at 0.0°C is completely filled with mercury at this temperature. When flask and mercury are warmed to 55.6°C, 8.68 cm of mercury overflow. - Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Expansion of mercury. Compute the coefficient of volume expansion of the glass. (The coefficient of volume expansion of the mercury is 18 x 10-5 K-?.). Express your answer in inverse...
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