Question

When a running football player “throws” his right foot down and behind him, as in this sketch, what happens in reaction is: He begins to fall backward. Counter-rotational torque applies. The ground pushes up and forward. The ground exerts no force on him.

Answer 1

Sl: since down PAQL 3 9td the player pushes На по шид and backwards according to newton's ground ю: 1 push the player in opposite direction i.eu and up forward. Option 3 correct О) 52- Electron from hydrogen atom is identical to an сесои РФ и охудем atom. (34 the CAR Ga - 2,5 Тя erage мо сим и dependent on temprature M = 0. от 5 - initial vеюі, "? wys friction force, 't this friction force wi decelerare clip f = ma a> - - О.o) О.019 м the - бle a = 1.9 m/s² deceleration So Sји је clip's it will oppose и Нои a- (№ 9 mus? final elo = 0 ", " - v- — Las g> v, 1-2 - 0 – (2-55 ca • 2-хі. 9 CS Scanned with CamScanner

S= 1.64 m distance is lo64 m Stopping 25 Heat required temperature to gold raise the from Ti to Ty in DQ= ml BT > mCCT-Til m = 1gm = 103 kg 000301 tallyk (specific heat q solid gold) 10 = 1X 0.03011337-1335) cal 60,- 0.0602 energy require d to melt gold. ДQ, = m2 しに Clontent heat tq AQ2 = 1815 = 15.10 q fusion ! total heat required 19> DQ, +AQ2 so 15.06 col. s CS Scanned with CamScanner