Question

63.

Use the following table of thermal physics specs. substance solid H20 liquid H2O solid gold liquid gold solid lead liquid lead specific heat melting/freezing Latent heat of (cal/g K) point (K) fusion (cal/g) 0.50 273 80 1.00 273 80 0.0301 1336 15 0.0355 1336 15 0.0305 601 5.5 0.033 601 5.5 HEAT-MELT-HEAT CALCULATION (3 points) How much energy is required to convert 1.00 gram of solid gold at intial temperature T; = 1335 K to liquid gold at final temperature Tp = 1337 K? Type in the numeric part of your answer to the nearest 0.01 calorie. E.g., if your calculation comes out to 390.2088 cal, then type in 390.21 and hit the SEND key.

Answer 1

fg solid gold to Ig liquid gold Orect = o to = 1x ist \x. 0.0 301 x (1336-1335) $ !¥6.6355 *. ( 1336-1337) = 1st 0.03014 0.0 301 + 00355 [Out = 15.0656 cal? So , Onut & is. I cal Aswer CS scanned with Cam Scanner