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A small block (s) of mass ms = 30 kg sits on a fixed ramp of angle a = 30 deg, height h = 4 m, and coefficients of friction s

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Soll Ms = 30kg = 30° Th th al 10 Toog 30g (ongo 0 Ma=0.3 ch=4m 30g Sin30 ls= 0.6 ma Ke 700NIM g = 10 m/s2 = 100 kg (10) &= ll(12) after System reach moving distance y by block B, the equilibe burium Ia Msglind - kx = 0 T = Ms g since tka 407 = 30x10If you have any doubt then mention in the comment

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