Question

In a physics lab, a small cube (M) slides down a frictionless plane, as shown in the figure, and statically strikes another cube (m) that is at the bottom and has only half the mass of the first. If the plane is 35 cm high and the table is 95 cm high measured from the floor

a) Where (in m) will the cube of mass M fall?
b) Where (in m) will the cube of mass m fall?

M 35 cm 95 cm

Answer 1

ha = 35cm = 0.35m H=95cm = 0.gsm M/2 L. 1 Vi= u, (m.-M2) - こ 3 mg h = /mv² Speed at bottom? - V - Sigh DM/2 V= 2x9.8 X0-35 = 2.62m's R2 Speed of block, m after collision Mitmz V, = 2-62x{-M/2) 2-b 2 xml 2.62 0.8733 ms. M+M 2 3m/2 Speed of block, M/2 2m, ki after collision V2 = 2x M X 2-62 Mitm2 m+m/ 2 X2-62X2 = 3.4933ms 3 Time taken to fall downfrom height , 120.95mis t EH 2x0.95 Song =0.44 sec. g 9.7 Distance avay from table, R = V,t = 0-8733 X0.44 R = 0.3842m R,= 38.42 cm. Distance of M/₂ away from table, R₂ =Vzxt = 3.4933X0:44 R₂ = 1.5370 m R2 = 153-70 cm 11 ol M