Question

A particle with a positive charge of 3 uC is moving parallel to a long (effectively infinite) wire carrying a current of 30 A. The particle's speed is 20 m/s and is the same direction as the current. The distance between the particle's path and the long wire is 0.5 m. (see figure below) (a) What is the magnitude of the magnetic field at the charged particle due to the long wire? (10 pt) (b) What is the direction of the magnetic field due to the long wire at the moving charged particle? (5 pt) (c) What is the magnitude and direction of the force on the charged particle? (10 pt) Explain how you determined the directions in parts (b) and (c). 3uc v=20 m/s 0.5 m 30 A

Answer 1

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to q=360 V-20mb. 10.sm 30A @ magnitude of magnetic fie feild is s given by where as is distance from B = Mol wire aar Mo 10 = No 2x10 21 42 X 0.5 5 - 1.2X10 T hand thumb b. direction is given by given by twright B sule I - Direction will be inside the plane. ② Magnitude of force , F = q VB = 3x10x20x 1-2x105 = 7.2x10ON Direction of force is given by left hand sule direction will be toward the wire 20m/s dovonward L q = 340