Question

Problem 3 A particle with charge of 2 (UC), mass of 2X10-20 (kg) and velocity of 200 (m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10$ (N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using RHR-1 D) In order to maximize the force, what should be the angle between velocity vector and magnetic field direction? What would be the value of the maximum magnetic force at this angle?

Answer 1

A) Force on m moving charged particle in magnetic field is qEx Fe qo ob sino = 1.01x10-5 = 2x10x200x 0.06 sin o 24.890 B) acceleration ө F m a 1.01x 10-5 2x 10-20 +14 5.05 x 10 m/s² goo > ✓ O = 94.899 get Force , is out of page D) to maximize force sino 2 maximum 1 » sino O-90° field Fmax = maximum force = 2.48103N velocity is perpendicular to magnetic

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