Given,
Charge, q = 2 x10-6 c
Mass, m = 2 x 10-20 kg
Velocity, v = 200 m/s
Magnetc field, B = 0.06 T
Magnetic force, F = 1.01 x 10-5 N
A) Angle
We know,
Magnetic force, F = q(v x
B)
F = qvB sin
= sin-1(F/qvB)
= sin-1 ((1.01 x 10-5)/(2 x 10-6
x 200 x 0.06))
= sin-1(0.42083)
= 24.89 degree
B) acceleration,a
F = ma
a = F/m
a = (1.01 x 10-5)/(2 x 10-20)
a = 5.05 x 1013 m/s2
C)
D) To maximize force,
sin
max = 1
max = 90 degree
Maximum magnetic force, Fmax = qvB
Fmax = 2 x 10-6 x 200 x 0.06
Fmax = 2.4 x 10-5 N
___________________________
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