Question

Please help is due in 30 mins, will rate, Thank you!

A phase change has ASsys = -17.250x10^1) J/K mol and AHsys = -(3.55x10^1) kJ/mol. At what temperature (in K) will this phase change be at equilibrium?

Answer 1

We know the following equation:

$\Delta G=\Delta H-T\Delta S$

Now, at equilibrium change in free energy becomes zero ($\Delta G=0$)

Therefore, $\Delta H=T\Delta S$

$\frac{\Delta H}{\Delta S}=T$

$\frac{-3.55*10^4(J/mol)}{-7.25*10^1(J/molK)}=T$

$489.65K=T$