Question

4. Please help is due in 30 mins, will rate, Thank you!

An aqueous solution has a mass percent of solute of (2.630x10^1)%. The density of the solution is (1.41x10^0) g/mL and the solute has a molar mass of (1.7000x10^2) g/mol. What is the molality of solute of this solution?

Answer 1

Assume Mass of solution Percent of solute Mass of solute 100.00 g 26.300 % (Percent of solution * Mass of solution) / 100 Mass of solute = Molar Mass of solute Moles of solute 26.30 *100/100 26.30 8 170.00 g/mol Mass of solute / Molar mass of solute 26.30 g 170.00 g/mol = 0.1547 mol = Mass of Water 0.0737 Kg Molality of solution 100 g - Mass of solute 100.00 g - 26.30 g = 73.70 Moles of Glucoise - Mass of solvent in Kg 0.1547 mol + 0.0737 kg = 2.10 m 2.10E+00 m