Question

9. Please help is due in 30 mins, will rate, Thank you!

When (8.8800x10^1) g of a non-electrolyte is dissolved in (5.84x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute?

Answer 1

Tь ATO skom To-To i kom For non electrolyte, é = 1 Boiling point of solution Too = Boiling point of Pure Solvent Kb %m molality No. of moles of solute weight of Solvent (in kg) wt. of Sotute xoco Moturwt. of solate & wt. of solvent (ing) STb = è lo m 0.416 B - ņ 5 1X0.4168 8.8 8 x 10 x 1000 5:84 x 100x Msolute Msolute = gran mole. My olete 42.1698 Solute Molar Mass Here solute is non-electrolyte in nature of solute) So, Molar Mass of non electrolyte = 42:1698 solute g/ 700 을 42.2 g/mol