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When (8.61x10^1) g of a non-electrolyte is dissolved in (5.3100x10^2) g of a solvent (with Kb...
9. Please help is due in 30 mins, will rate, Thank you! When (8.8800x10^1) g of a non-electrolyte is dissolved in (5.84x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute?
At an unknown temperature a solution made of (5.180x10^0) g of a non-volatile solute dissolved in 100.0 g of water has a vapor pressure of (5.54x10^1) mm Hg. What is the vapor pressure of pure water (in mm Hg) at this unknown temperature? The molar mass of the solute is (4.620x10^1) g/mol. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is...
1h. A certain pure solvent freezes at 39.8°C and has a freezing point depression constant Kf = 0.777°C/m. What is the predicted freezing point (in °C) of a solution made from this solvent that is (1.90x10^0) m in a non-electrolyte solute? 1i. When (8.23x10^1) g of a non-electrolyte is dissolved in (5.2600x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the...
When 9.31 g of an unknown non-electrolyte is dissolved in 50.0 g of benzene, the boiling point increased by 3.16 degrees C. If the Kbp of the solvent is 2.53 K/m, calculate the molar mass of the unknown solute. The answer is 149 ± 2% looking for explanation how to work this problem
When 8.59 g of an unknown, non-volatile, non-electrolyte, X was dissolved in 100. g of benzene, the vapor pressure of the solvent decreased from 100 torr to 97.5 torr at 299 K. Calculate the molar mass of the solute, X.
An aqueous solution has a mole fraction of solute of (3.660x10^-2). The density of the solution is (1.20x10^0) g/mL and the solute has a molar mass of (8.3800x10^1) g/mol. What is the Molarity of solute of this solution? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...
How many grams of Mg(NO3)2 (MM = 148.33 g/mol) would it take to lower the freezing point of (4.95x10^2) grams of water by 4.00°C? The freezing point depression constant of water is Kp = 1.86°C/m. Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: X10 Answer
when 4.90 g of a non electrolyte solute is dissolved in water to make 505ml of solution at 24 C, the solution exerts an osmotic pressure of 803 torr. what is the molar concentration of the solution? How many moles of solute are in the solution? What is the molar mass of the solute?