When 9.31 g of an unknown non-electrolyte is dissolved in 50.0 g of benzene, the boiling point increased by 3.16 degrees C. If the Kbp of the solvent is 2.53 K/m, calculate the molar mass of the unknown solute.
The answer is 149 ± 2%
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When 9.31 g of an unknown non-electrolyte is dissolved in 50.0 g of benzene, the boiling...
When 8.59 g of an unknown, non-volatile, non-electrolyte, X was dissolved in 100. g of benzene, the vapor pressure of the solvent decreased from 100 torr to 97.5 torr at 299 K. Calculate the molar mass of the solute, X.
When (8.61x10^1) g of a non-electrolyte is dissolved in (5.3100x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to...
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
A solution contains 10.35 g of unknown compound (non-electrolyte) dissolved in 50.0 mL of water. (Assume a density of 1.00 g/mL for water.) The freezing point of the solution is -3.26 ∘C. The mass percent composition of the compound is 60.98% C, 11.94% H, and the rest is O. What is the molecular formula of the compound?
1. When 1.00 g of an unknown, nonvolatile, nondissociating solute is dissolved in 50.0 g of camphor, the solution melts at 173.4 C. If pure camphor melts at 178.4 C and has Kf = -37.7 K kg mol', what is the approximate molar mass of the unknown solute?
1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...
when 4.90 g of a non electrolyte solute is dissolved in water to make 505ml of solution at 24 C, the solution exerts an osmotic pressure of 803 torr. what is the molar concentration of the solution? How many moles of solute are in the solution? What is the molar mass of the solute?
A solution contains 11.70 g of unknown compound (non-electrolyte) dissolved in 50.0 mL of water. (Assume a density of 1.00 g/mL for water.) The freezing point of the solution is -7.01 ∘C. The mass percent composition of the compound is 38.70% C, 9.74% H, and the rest is O. What is the molecular formula of the compound? Express your answer as a molecular formula So far I got CH3O as my empirical, but I can't seem to figure out how...
9. Please help is due in 30 mins, will rate, Thank you! When (8.8800x10^1) g of a non-electrolyte is dissolved in (5.84x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the molar mass (in g/mol) of the non- electrolyte solute?
A solution is prepared by dissolving 11.10 g of an unknown non-electrolyte solute in 78.64 g of cyclohexane. The freezing point of the solution is found to be 2.06 oC. What is the molar mass of the unknown solute in g/mol? Please report your answer with 3 significant figures. Answer g/mol