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1. When 1.00 g of an unknown, nonvolatile, nondissociating solute is dissolved in 50.0 g of camphor, the solution melts at 17
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Answer #1

Change in freezing point = kf x molality

178.4-173.4 = 37.7 x morality

morality = 0.13262

number of moles of solute per kilogram of the solvent = 0.13262

number of moles of solute in 50 g of the solvent = (0.13262/1000) x 50 = 0.006631‬

number of moles = mass in g/molar mass

0.006631‬ = 1/molar mass =

molar mass = 150.806 g/mole

molar mass of the unknown = 150.806 g/mol

please note that kf cant be negative quantity

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