6. A 1.07 mg sample of a compound was dissolved in 78.1 mg of camphor. The...
6. A 1.07 mg sample of a compound was dissolved in 78.1 mg of camphor. The resulting solution melted at 176.0 C. What is the molecular mass of the compound? The melting point of pure camphor is 179.5 C. The freezing-point-depression constant for camphor Kf is 40.0 C/m.
7. A solution is prepared by dissolving 5.88 g of an unknown nonelectrolyte in enough water to make 0.355 L of solution. The osmotic pressure of the solution is 1.21 atm at 27 C. What is the molar mass of the solute? (R = 0.08206 Latm/molK)
Homework Answers
Add Answer to:
6. A 1.07 mg sample of a compound was dissolved in 78.1 mg of
camphor. The...
A 1.07 mg sample of a compound was dissolved in 78.1 mg of camphor, a solvent...
A 1.07 mg sample of a compound was dissolved in 78.1 mg of camphor, a solvent that melts at 179.5 *C and has an unusually high Kfp of 40.0 *C/molal. The freezing point of the resulting solution dropped to 176.0 *C. a. Calculate delta t fp b. Calculate the molality of the solution c. Calculate the moles of solute in the solution d. Calculate the molar mass of the compound
(6 pt) 4 A 1.07-mg sample of a non-ionic compound was dissolved in 78.1 mg of...
(6 pt) 4 A 1.07-mg sample of a non-ionic compound was dissolved in 78.1 mg of camphor, a solvent that melts at 179.5°C and has an unusually high Kr of 40.0 mola If the freezing point of the solution is 176.0°C: a) Calculate AT, then determine the molality (m) of this solution: b) Calculate the moles of solute in this solution: e) Calculate the molar mass ()of e coound:
A solution is prepared by dissolving 0.107 g of an unknown non-electrolyte in 88.1 g of...
A solution is prepared by dissolving 0.107 g of an unknown non-electrolyte in 88.1 g of camphor. The freezing point of the solution was measured to be 178.0�C. What is the molecular weight of the compound? (The freezing point of pure camphor is 179.5�C and kf= 40�C/m)?
A 275 mg sample of a nonelectrolyte compound was dissolved in water to produce 10.0 mL...
A 275 mg sample of a nonelectrolyte compound was dissolved in water to produce 10.0 mL of a solution at 25°C. The osmotic pressure of this solution was measured and found to be 3.67 atm. What is the molar mass of this compound? O 183 g/mol 18.3 g/mol 101 g/mol 1560 g/mol 1830 g/mol Question 25 (1 point) Which statement below is true? O Nonpolar molecules can dissolve in polar solvents. Gases are soluble only in nonpolar solvents. lonic compounds...
A sample of 4.6434 g of benzoic acid, C_7H_6O_2, is dissolved in 50.0033 g of camphor....
A sample of 4.6434 g of benzoic acid, C_7H_6O_2, is dissolved in 50.0033 g of camphor. what is the freezing point of the resulting solution? For camphor, T_f = 179.5 degree C, K_f = 40.00 degree C/m.
A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene....
A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene. Calculate the freezing point, Te, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. T = Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* Normal freezing Kb value Normal boiling (°C/m) point (°C) (°C/m) point (°C) water H20 1.86 0.00 0.512 100.00 benzene 5.12 5.49 2.53 80.1...
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g...
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...
A solution is made by dissolving 0.585 mol of nonelectrolyte solute in 877 g of benzene....
A solution is made by dissolving 0.585 mol of nonelectrolyte solute in 877 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8...
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved...
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
Eicosene is a molecular compound and nonelectrolyte with the empirical formula CH2. The freezing point of...
Eicosene is a molecular compound and nonelectrolyte with the empirical formula CH2. The freezing point of a solution prepared by dissolving 100mg of eicosene in 1.00g Benzene was 1.75 degrees C lower than the freezing point of pure benzene. What is the molar mass of eicosene if Kf for benzene is 4.90 Degrees C/m?
(6 pt) 4 A 1.07-mg sample of a non-ionic compound was dissolved in 78.1 mg of camphor, a solvent that melts at 179.5°C and has an unusually high Kr of 40.0 mola If the freezing point of the solution is 176.0°C: a) Calculate AT, then determine the molality (m) of this solution: b) Calculate the moles of solute in this solution: e) Calculate the molar mass ()of e coound:
A 275 mg sample of a nonelectrolyte compound was dissolved in water to produce 10.0 mL of a solution at 25°C. The osmotic pressure of this solution was measured and found to be 3.67 atm. What is the molar mass of this compound? O 183 g/mol 18.3 g/mol 101 g/mol 1560 g/mol 1830 g/mol Question 25 (1 point) Which statement below is true? O Nonpolar molecules can dissolve in polar solvents. Gases are soluble only in nonpolar solvents. lonic compounds...
A sample of 4.6434 g of benzoic acid, C_7H_6O_2, is dissolved in 50.0033 g of camphor. what is the freezing point of the resulting solution? For camphor, T_f = 179.5 degree C, K_f = 40.00 degree C/m.
A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene. Calculate the freezing point, Te, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. T = Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* Normal freezing Kb value Normal boiling (°C/m) point (°C) (°C/m) point (°C) water H20 1.86 0.00 0.512 100.00 benzene 5.12 5.49 2.53 80.1...
Most questions answered within 3 hours.
-
Suppose a particle has zero potential energy for x
< 0, a constant value V, for...
asked 8 minutes ago -
A normal distribution of scores has a mean of 240 and a standard
deviation of 40....
asked 3 minutes ago -
Create a Namespaces.h header file containing a namespace
declaration yourname. The declaration should include a method...
asked 12 minutes ago -
Herrod Catering uses two measures of activity, jobs and meals,
in the cost formulas in its...
asked 11 minutes ago -
As a technician in a large pharmaceutical research firm, you
need to produce 200. mL of...
asked 13 minutes ago -
how a person can still function with different parts
of the brain being damaged or removed
asked 15 minutes ago -
Cells that contain two of each of the chromosomes in a set are
known as:
Haploid...
asked 25 minutes ago -
The United States Department of Agriculture (USDA) found that
the proportion of young adults ages 20–39...
asked 29 minutes ago -
two part question: PLEASE ANSWER BOTH PARTS.
THANKS
A: Dyl Inc's bonds currently sell for $1,180...
asked 30 minutes ago -
What are the relationships and distinctions between
the exercise of power and compliance gaining?
asked 40 minutes ago -
A student ran the following reaction in the laboratory at
283 K:
2CH2Cl2(g)
->CH4(g) +
CCl4(g) ...
asked 41 minutes ago -
Write a Prolog program to find the maximum, minimum, and range
of values in a list...
asked 46 minutes ago