Question

Part III: Application 16 Marks 18. Identify the type of reaction. Write the correct chemical formulas of the compounds. complete and balance the equations and name the products formed. a) calcium carbonate + hydrochloric acid → b) iron + sodium bromide → c) ammonium acetate + + iron(II) chloride → (A-6) 19. Convert cach of the following to moles. a. 8.8 g of potassium carbonate b. 0.257 g of arsenic pentachloride c. 5.00 x 10"atoms of iron

Answer 1

Type of reaction, correct chemical formula of compound and balance the equation & name of Product formed. u Calcium carbonate + Hydrochloric acid In the reaction we get the product as calcium chloride water & Carbon dioxide * Type of reaction Double Displacement reaction. * Chemical formula: calcium carbonate = CaCo3, Hydrochloric acid = He, calcium chloride = cach, water = H2o, Carbon dioxide=co2 Balance chemical equation. Caco3 + 2HCl caca calcium chloride + H2O + CO2 water Carbon Dioxide 2) iron it sodium bromide * Type of reaction = Single Displacement chemical formula: Iron - Fe , sodium bromide - NaBr & Product formed a Ferric Bromide f sodium (Fe Braz) (Na) ) * Balance chemical equation Fe + 3 Na Br febry + 3 Na Iron sodium Ferric Sodium Scanned with Bromide Bromide CS CamScanner

3) ammonium acetate & Iron (1) chloride & Type of reaction - Double Displacement * Product formed in the reaction Ammonium chloride Iron (11) Acetate chemical formula ammoniam acetate = C₂ H₂ NO2 Iron (11) chloride = Fech X 1 Iron (1) Acetate = Felcz H302)2 ) Ammonium chloride NH4Cl * Balance chemical 2 CzH7NO2 + Fella Ammonium Iron(11) Acetate chloride Scanned with CamScanner equation FelCq Hz O2)2 + 2NH4C1 Iron ci) Ammonium Acetate chloride CS

8.8 9 convert each of the following to moles. of potassium carbonate potassium carbonate (K2003) = 138.205 g/mol (molecular mass) No. of moless mass of kz C63 molar mass of Kalog 8.8 (9) 138.205 (31 moi) 0.0 64 mole Noo of moles in 8.8 g of pottasium carbonate = 0.064 mole 2) 0.257 g of arsenic pentach loride. arsenic penta chloride = (ASCIS) = 252.18 g/mol (molar mass.) No. of moles= mass of Asas molar mass of Asas 0.257(0) 252.18 (91701) =0.ool olg mole ř 1.01g x103 mole - The number of moles Arsenic Pentachioride Scanned with CS CamScanner in 0.287 g of 1.01g x103 mole

() S00x1023 atoms of iron. We know that Imole of substance Contain .6.023x123 atoms. . so by using this relation, we can calculate atoms &moles also of Iron no. of 23 6.023 x 10 atom i mole 23 sxio? atom = X mole X moles Imole x SX1023 octóm 6.023x123 atom X mole = 0.830 mole of Iron no. of moles present in sx1023 atoms of Iron a 0-830 moles CS Scanned with CamScanner

Q1)

a. CaCO3 + 2HCl → CaCl2 + H2O + CO2

Double displacement reaction .

b. Fe + 3NaBr → FeBr3 + 3Na

Single displacement reaction .

c. 2C2H7NO2 + FeCl2 → Fe(C2H3O2)2 + 2NH4Cl

Double displacement reaction .

Q2) convert each to moles

a. 8.8 g of potassium carbonate = 0.064 moles

b. 0.257 g of arsenic pentachloride = 1.019×10-³ moles

c. 5.00×10²³ atoms of iron = 0.830 moles