Write the following expression as an algebraic expression. V3 tan where x > 0 V22 +
Write the following as an algebraic expression involving only x. Assume x <0. sin(arcsin x + arccos x)
Write each expression as an algebraic (nontrigonometric) expression in u, u>0. sin (2 sec - 15) sin (2 sec ) = 0 (Simplify your answer.) Solve the equation for an exact solution. arccosx+2 arcsin 123 = 1 The solution set is . (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
Write the expression as an algebraic (nontrigonometric) expression in u, u> 0. cos (arctanu) cos (arctan u) = 0 (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Rationalize all denominators.) The following function approximates the average monthly temperature y (in °F) in a city. Here x represents the month, where x= 1 corresponds to January, x=2 corresponds to February, and so on. Complete parts (a) (b). flx) = 11 sin [«- 49]+50...
2. Assume X is a random variable following from N(μ, σ2), where σ > 0. (a) Write down the pdf of X (b) Compute E(X2). (b) Define YFind the distribution of Y.
> Δ 50% Part (a) Write an expression for the liquid's index of refraction, n. n= HOME 0 Submit I give up!
7. Let X1,... , Xn be iid based on f(x; 6) -22e-z?/e where x > 0. Show that θ=-yx? is efficient
write tan[ arccos(x) ] as an algebraic expression in x, given x >0
2 Write the given algebraic expression as a function of e, where 0 <e< by using the substitution given: a) x = 6 cos in 36 - x2 b) x = 2 tane in Vx2 + 4
State the quadrant in which lies. sin(8) <0, cos(8) < 0 OII III OIV 8 If sin() and 8 is in the 1st quadrant, find the exact value for cos(8). 9 cos(8) - > Next Question State the quadrant in which lies. tan(8) > 0, csc(8) < 0 01 OII O III OIV
The exothermic reaction, A--> has AG<0. Which of the following statements are true AH<0 for the reaction AS must be greater than zero AS could be greater than or less than than zero the reaction is spontaneous in the reverse direction