Question

8 decay Before B decay Before After After V. Parent Daughter Parent Daughter nen AP → D+e+v P-D + entry electron neutrino Anti- decay A cobalt Co nucleus (27 protons, 60 nucleons) go through a decay. (a) Find the number of protons and the number of nucleons in the Daughter nucleus. Enter the number of protons in the first box, and number of nucleons in the 2nd box. Enter a number Submit (5 attempts remaining) Enter a number Submit (5 attempts remaining) The relevant rest masses are: Parent Co = 59.933820 u, total of (daughter + B particle) = 59.930789 u. (b) What is the mass defect in atomic mass unit u? Keep 6 decimal places. Report the mass defect as positive. Enter a number 4 Submit (5 attempts remaining) What is the energy (in MeV) corresponding to the mass defect? Keep 3 decimal places. (1uc? = 931.5 MeV) Enter a number MeV Submit (5 attempts remaining) Is energy released in this decay or must energy be supplied for the decay to occur? Select your answer from one of the following options. a. Energy is supplied, since the total rest energy before the decay is smaller than the total rest energy after the decay. b. Energy is released, since the total rest energy before the decay is smaller than the total rest energy after the decay. C. Energy is supplied, since the total rest energy before the decay is larger than the total rest energy after the decay. d. Energy is released, since the total rest energy before the decay is larger than the total rest energy after the decay. Submit (5 attempts remaining) pt decay A sodium Na nucleus (11 protons, 22 nucleons) go through a ßt decay. (a) Find the number of protons and the number of nucleons in the Daughter nucleus. Enter the number of protons in the first box, and number of nucleons in the 2nd box. Enter a number Submit (5 attempts remaining) Enter a number

Answer 1

In general for ß decay 2 43 x' + e +ve 1 Daughter nudeus a) In the question, Nickel 60 60 B D+ě +ve 27 28 28. So, 60 proton number will be nudeon neember will be in the daughter nudeus. b) Mass defect, am =-m [A, 2+)] + m [A, z] n = m mass 6) mass defect, of parent Co - mass of (daughter + ß particle) = (59.933820 - 59.930789) 4 - Nu 0.003031 u Energy equivalent of mass defect E = Ne x 931.5 MeV/ 0.003031 x 937.5 2 2.82 Mev Mev

From mass defect we can see that it's positive. So total energy before decay is greater than the energy after decay. So, energy released. Hence, 4th option (d) option d is correct. In general for ßt decay, A x 1X + ßt a ve 2 2-1 Here question, Neon 22D + B + tve geNa ßt 10 So, number of protons are so and nucleons 22. are