Question

This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission Nuclear Physics - Nuclear Fission 2 Nuclear Fission 2 on+233 U— ' Ba+ 4 X +3 'n The above figure shows a neutron induced fission reaction of 235U (92 protons, 235 nucleons). (a) Find the number of protons and the number of nucleons i the nucleus labeled X. Enter the number of protons in the first box, and number of nucleons in the 2nd box. Enter a number Subm (5 attempts remaining) Enter a number Submit (5 attempts remaining) The relevant rest masses are: 235U = 235.043924 u, 141Ba = 140.914411 u, X=91.926165 u, neutron n = 1.008665 u. (b) What is the mass defect in atomic mass unit u? Keep 6 decimal places. Report the mass defect as positive. Enter a number u Submit (5 attempts remaining) What is the energy (in MeV) corresponding to the mass defect? Keep 3 decimal places. (1uc2 = 931.5 MeV) Enter a number MeV Submit (5 attempts remaining) Is energy released in this decay or must energy be supplied for the decay to occur? Select your answer from one of the following options. a. Energy is supplied, since the total rest energy before the reaction is smaller than the total rest energy after the reaction. b. Energy is supplied, since the total rest energy before the reaction is larger than the total rest energy after the reaction C. Energy is released, since the total rest energy before the reaction is smaller than the total rest energy after the reaction d. Energy is released, since the total rest energy before the reaction is larger than the total rest energy after the reaction. Submit (5 attempts remaining)
I can answer the multiple choice, I just need help with the fill ins.

Answer 1

solution - @ А 235 U 92 1.41 Bat In 3. lich 2x S ( 3x0 or 9 2 = 56 + Zt pholow Z=36 Nuction 235 - lule A+ 3x1 A = 92 A = Z AN Na nuleous E N = 56 92 = 36+N مر) Dom & are 92 mul Ba + 3oX Am = 2350 ) + 3x in ) óht 56 92 235.043924 + 1:008665) o ( 140.914411 + 91.926165 + 3x 1.008665) Om 0.1860 18 u Ame²= O. 1860 18 x 9 31.5 Mev " 0.18 6018 402 173.275767 Meu

Option - d is correct

As per HomeworkLib policy we can answer only first question.