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(1 point) A resistor and a capacitor are in series with an AC source. The impedance is Z 210 H. Find R and C. 10.522 at 410Ha
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Answer #1

Xc = too g w=aaf Z = 5R²+ Xc² z² = R²+xc² 22 * = 10.52g xc, = Love = R²txe? 9 W, = 8205 K2=18.6.2 g AC2 = W 2C W2 = 4200 K2 R(4201) c? (8201)2c2 in 2 4.2378107 = 228.3162 С 43.08 elf put value of @ in eq; 90.5)² = 0P² ! (8207) (4308X189? IR = 5.392

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