Question

Att -0 a grinding wheel has an angular velocity of 26.0 rad/s. It has a constant angular acceleration of 25.0 rad/s until a circuit breaker trips at time t = 1.70 s. From then on, it turns through an angle 438 rad as it coasts to a stop at constant angular acceleration Part A Through what total angle did the wheel turn between t = 0 and the time it stopped? Express your answer in radians | ΑΣΦ 2 8 = rad Submit Request Answer Part B At what time did it stop? Express your answer in seconds. ΟΙ ΑΣφ ?

a b and c please

Answer 1

Initial angular velocity Wi-280ad/s Angular acceleration &, = 25 rad/32 circuit breaker tripy at time t, = 1.7sec After circuit breaker toify angular displacement made by wheel before comming to rest og = 438 rad 0, = w:t, + fat? 0, = (@6x107) + ( x 25x(1.3)”) 0,- 44.2+ 36.125 0,= 80.325 rad Angular displacement before comming to rest o=0,+02 O=80.325+438= 518.325 rad angular velocity at t=1-75 wi+at, = 86+425x1.7) = 26+u8.5 Wof, = 68.5 radls final velocity wfg=0 rad/s wif - will = QdO₂ 8²_(68.5 = 2x2₂x638 de -(68.52 _-4692.25 =-5.357 radf? 15 accelenation ag it slowed down y 2,=-5.35789067 Wote = wftate 0 = 68.5+ (-5.357x) lofi 2 xu38 876 t = 68.5 -12.79 sec 5.357 Ist wass stopped at t= titty = 1.7+12.79 = 14.488sec