Question

Question 14 3 pts A 250-turn rectangular coil having dimensions of 8.0 cm by 3.0 cm is placed in a uniform magnetic field of magnitude of 0.9 T. Assume the max torque exerted on the wire by the magnetic field is 0.13 Nm. Find the magnitude of the torque on the coil when the magnetic field makes an angle of 28° with the normal to the plane of the coil.

Answer 1

Que A 250-turn Rectangular coil haring dimensions of 8.0cm and by 3.0cm cm is placed in a uniform magnetic field of magnitude 0.9T. Assume the max torque exerted on the field is 0.13 Nm. find the magnitude of the torque on the coil lohen the magnetic field makes and angle of do with the normal to the Plane Coil . wire day the magnetic of Solution Normal to plane B = magnetic field To find magnitude of torque = ? 25 3cm 20.03m fio cm 0108 m we for multiple turns N on a coil, the Now know that expression of tosque giren as 2- NIA B Sine if we take first section of question in which we are maximum torque amare 0.13 Nm then we can find I ine. Ausent loop and an ere that value to pursue the 2nd Part given with

Now given Parametess are N = 250 turns ? more = 0.43 Nm Uniform - B B = 0.9 T Magnetic field A = WAL= 8x3 cme 0.08*0,03 m2 0.0024 ma = 2.4 x 10-3 m2 and for maximum torque sino should also be marimum inc. Sino = line. o = 90° Now using equation 0 & above Parameters we get NIA Bding Za 250 XI X 0.0024 x 0,9 x(Sine) max Zmoor 1000 - U 0.13 = 250 X 0.0024 x0,9 * !* I 0.13 0.241 =) I > 0.54 Now to Hat we need to find magnitude of torque, when magnetic field is making angle of es with normal Plane ire. Or do again we equation 2=NI AB sino - r = 250 X 0.241X0.0024 x 0.9 X Sinas here again -> =) z = 0.13014 X 0.469 Z = 0.0610 Nm] Ans

NOTE I hope know about units you 2= NI AB sino if we expand it Z= NI W x L B Sino A unitless »2-NWBIL (Sino force funits are Newton width units are m o 2 has units Newton meter Nm >