Question

In a long jump, an athlete leaves the ground with an initial angular momentum that tends to rotate her body forward, threatening to ruin her landing. To counter this tendency, she rotates her outstretched arms to "take up" the angular momentum (see the figure below). In 0.650 s, one arm sweeps through 0.500 rev and the other arm sweeps through 1.000 rev. Treat each arm as a thin rod of mass 3.9 kg and length 0.59 m, rotating around one end. In the athlete's reference frame, what is the magnitude of the total angular momentum of the arms around the common rotation axis through the shoulders?

Answer 1

(0.50 ver) (2Ti rad 4.8332 Yad/s rev 0.650s (i vev) (PTT radser ونها 9.6664 yad's 0.650S LI T = 29 30 =(3-9 18) 6.59m) que 4.8332 xad/s = 6.5615 kg.my 12 = IW2 = (3.9kg) (0.59m) Cu 5664 xadrs) = 13. 1230 Kg.nu/ from the athlete's reference frame, L=ha-L 6.5615 kg.m/