The kinetic energy, E= 4.4*10^-19 J
Mass of electron, m = 9.109*10^-31 kg
We know,
So, (Answer)
> Question 15 3 pts An electron moves in a circular path perpendicular to a magnetic...
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.38 T. If the kinetic energy of the electron is 4.4x10-19 J. (me = 9.109 × 10-31 kg) (a) Find the speed of the electron. 1.903 8.512 2.692 6.019 (b) Find the radius of the circular path. 3.712 1.375 7.795 2.062
utes 12 hours and 50 minutes) Question 16 3 pts An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.38 T. If the kinetic energy of the electron is 4.4x10-19).(m. - 9.109 10318) (b) Find the radius of the circular path, . 2.062 mc016-1.jpg 7795c016-2.jpg 1.375.mc016-3.log 3712mc016-4logm None of the above
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Problem 4. (10 pts.) A proton moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.00 mt. If the speed of the electron is 1.52 x10 m/s, determine (a) the radius of the circular path. (c) the time interval required to complete one revolution.
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An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 1.00 mT. The angular momentum of the electron about the center of the circle is 2.50 times 10^-25 J-s. Determine the radius of the circular path. cm Determine the speed of the electron.
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