Question

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T....

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electron is 4.30 ✕ 10−19 J, find the speed of the electron and the radius of the circular path.

(a) the speed of the electron m/s

(b) the radius of the circular path μm

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Answer #1

9 = e = 10x104C B = 0.275 T K.E = 6.3 x 109 I m2 Kinetic eneagy Imv?= 6.3 x 109 J 2x4.3x1019 9.1x1031 2x4.3 7119 9.1x103)

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