Question

An object of mass 3M, moving in the +x direction at speed vo, breaks into two pieces of mass M and 2M as shown in the figure. V = ? 2M 3M O = 0 If 01 = 63.0° and 02 22.0°, determine the final velocities Vi and v2 of the resulting pieces in terms of vo. M V = ? V1 = VO U2 = VO

Answer 1

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2 kmO₂ 2m V₂coso vo D sm db leso, Nandi in [ma mit me ride 1.M conservation of liniar momentin Mom, u + med [Take velocity component in livar diren as the initial relocity → (3m) v = (2m) (660x83) + (m) [vitaso.) M23m, Vavo, m, 22m, mm IV, avond, v. 2, caso, em 3 v. = 2% cos 22 & &. cos63 [cancelling in from both correderation of Kinetic energy [in the direer of vo, e. in x dire con] Mov - , , + & me BV-2 V.22-6424 (zm) (vo) = (2 m) { conde) + (m) (1, 200² from (i)) > 3o = 2 x 522 de x cor63 > 3. & 2 cos 22 + 3.-2₂ 0822 & ca563 [from;)] 282 & V₂ = Vocos22 -To 9270. Vev, 22/00 on 2 cos a3 3-2008 22 8343 3-2can 22 to cas 63 2 day 2 cas63 do - 22 05 22 +98 + 402 522 - 12.₂ 0522 a car 227 - RVV kes 22 = 0 +