Question

2M V = ? An object of mass 3M, moving in the +x direction at speed vo, breaks into two pieces of mass M and 2M as shown in the figure. If 01 = 70.0° and 02 = 24.0°, determine the final velocities v1 and v2 of the resulting pieces in terms of vo- 3M M V1 = VO v2 = VO

Answer 1

Conservation of momentum : Horizontally initial momenton - final momentum - 30 v 2M. & Co O₂ + MV, coso, 3 V - 2 v cos (24") + V, os (700) Vertically initial vertical momentum food rertical momention 2 M, V Sin O₂ M. v, sino - 2 sin (24) from 0 and ... (using: U. = V sin (700) 2U Sin(24) Sin (70) 3V0 = 2 Uz Cos (240) + 2 V2 x Sinly) & cos (70) Sin (70°) - 31. = 20Cos (24) + 2 z Sinky & Cot (70) ) 3V ur (20s (24) + 2 sin (24) cot (700)) = ) 2 30. 2 cos (240) + 2 sin (24) Cot (70) 2) v2 1o HIV. Via 1.22 V.

V1=1.22 v0

V2 = 1.41 v0

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