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plz keep in mind sig figures and answer all 3 parts :)A 5.70-m length of 2.6-mm-diameter wire carries a 690 mA current when 23.0 mV is applied to its ends. reen Sh 07...13.1 Part

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2.6mm => = D= 1.371003m Given l= 5.70m D (= 690mA= 0.69 A E = 23.0mV = 2.3x10? V e=iR A) R= 2.3x102 &li 0.69 R = 33.33MR B Si

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