How many milliliters of a 9.0 M K2SO4 solution are needed to make 0.55 L of a 3.5 M solution?
Since M1V1 =M2V2
Therefore v1 = .55 L = 550ML
M1 = 3.5 M
M2 =9M
So V2=3.5×550÷9
V2=213.8ML
How many milliliters of a 9.0 M K2SO4 solution are needed to make 0.55 L of...
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