Question

How many milliliters of 4.57 M potassium bromide solution would be needed to prepare 1.00 L of 2.08 M potassium bromide solution?

Answer 1

Molarity of solution 1 (M1) = 4.57 M ....(given)

Molarity of solution 2 (M2) = 2.08 M ....(given)

Volume of solution 2 (V2) = 1 L or 1000 ml ..(given)

(because We know 1 litre = 1000 ml )

Volume of solution 1 (V1) = ?

We know, that concentration Equation is -

M1V1 = M2V2

So,

4.57 M × V1 = 2.08 M × 1000 ml

V1 = 2.08 M × 1000 ml / 4.57 M

V1 = 455.14 ml

Hence the amount in milliliters of 4.57 M potassium bromide solution would be needed to prepare 1.00 L of 2.08 M potassium bromide solution is 455.14 milliliters.