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Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750 A for 1.2 hour (1 hour = 3,600
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Answer #1

0.75A for 1.2 homs. Supplies (0.75*1-2x3000) Condant change. - 3240 Coulomb If АЛ +3 > AL so 3x 965000 contomt change can dep

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