Answer:
Option A:
Fe has atomic number of 26
So number of nuetron in
57Fe = 57-26 = 31
56Fe = 56-26 = 30
58Fe = 58-26 = 32
So we don't have the same neutron in all the pairs
Option B:
Fe has atomic number of 26
So number of nuetron in
57Fe = 57-26 = 31
Mn has atomic number of 25
55Mn = 55-25 = 30
Co has atomic number of 27
58Co = 58-27 = 31
So we don't have the same neutron in all the pairs
Option C:
Fe has atomic number of 26
So number of nuetron in
57Fe = 57-26 = 31
56De = 56-26 = 30
Co has atomic number of 27
58Co = 58-27 = 31
So we don't have the same neutron in all the pairs
Option D:
Fe has atomic number of 26
So number of nuetron in
56Fe = 56-26 = 30
Mn has atomic number of 25
55Mn = 55-25 = 30
Co has atomic number of 27
57Co = 57-27 = 30
So we have the same neutron in all the pairs so this should be the correct answer
Option E:
Fe has atomic number of 26
So number of nuetron in
56Fe = 56-26 = 30
Mn has atomic number of 25
54Mn = 54-25 = 29
Co has atomic number of 27
57Co = 57-27 = 30
So we don't have the same neutron in all the pairs
So correct answer is fourth opiton 56Fe, 55Mn and 57Co
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