In the complex , the metal atom, is . So, from the electron count of the complex and knowing that cyanide is a strong field ligand, we can conclude the answer (I) but certain things are important to discuss so that we can solve these problems with ease.
[ To calculate the charge of the central metal atom Co, assume its charge is 'x', now 6 cyanide ligands have '-1' charge each making a total of '-6' and the overall complex has a charge of '-3'. So, . So, Co is in the oxidation state of '+3' in the complex. Now, Co has a configuration of , so to make , we first have to remove the two 4s electrons and one 3d electron which makes it a complex.]
Now, is a strong field pi-acceptor ligand (from spectrochemical series!) which means in the co, complex, it makes a higher energy barrier between the and sets of orbitals. Now, to place the six electrons, we cannot use the as the energy of the complex cannot be compensated in that case, so we have to place all the six electrons in the orbital only. So, the remains vacant and our configuration becomes the one that is depicted in .
Vp Patio tend to undergo positron emission. Question 5 What is the crystal field energy level...
What is the crystal field energy level diagram for the complex [Co(CN).13-? d1 라리라 , 씀씀을 은은 (1) (IV) O II and III only OIV only O Tonly O ll only o I and IV only
Question 19 7 pts What is the crystal field energy level diagram for the complex [Co(CN)613-? 个个 个个 d ² d ² ? dd 2-3 d² d ² ? d, dx?? 个 1个 TV /个 11个 dxy dx dy d. dy d d. d xz d d xy dx dy (0) (II) (IV) 분쓴씀 뜻송송 N NZ XY Z IV only 0 I and IV only O l only Il and Ill only 0 O ll only
What is the crystal field energy level diagram for the complex [Co(CN)613-? 2 did 2 Xy d, ↑ ↑ ↑ d xy d xz dyz 1 1 d?d?? ^ ^ ^ d xv d d, 1 1 1 1 d xy dxz d 1 d d xz dyz dxi ху yz yz (1) (11) (111) (IV) IV only O Il only I only I and IV only II and III only
show all steps please What is the crystal field energy level diagram for the complex (Co(CN).1? 11 did! ttt! 1 1 11 ddd dy dud d. de do 2.1 (1) (111) (IV)