Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CHO H OH...
Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CHO H ОН HO -H CH,OH OD, triose. ketose, 1 OL, triose, ketose, 1 OL, tetrose, aldose, 2 OD, tetrose, aldose, 2
Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CHO HO H H OH HO -H CH2OH OL, pentose, aldose, 3 OL, tetrose, ketose, 2 OD, tetrose, ketose, 2 OD, pentose, aldose, 3
Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CH2OH Н. -OH CH OH OL, triose, aldose, o OL, tetrose, ketose, 1 D, tetrose, ketose, 1 D, triose, aldose, o The product formed by the following reaction sequence is 1) HNOZ/H2SO4 2) C12, AICI: 3) Fe, HCI 4) NaNO,, HC1 5) KCN Identify the best method to prepare 5,5-dimethylhex-2-ene? CH2CH2CH2CH=PPhz + (CH3),C=0 OCH2CH=PPh: + (CH3)3CCH=0 O(CH3)3CCH2CH=PPhz + CH2CH=0 OCH3CH,CH=PPhz + (CH2CH2)2C=0
Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CHO H OH HO H HO -H HO -H CH2OH
Question 17 (4 points) Which molecule is the strongest base? NH2 NC NH NH2 Question 18 (4 points) Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CH2OH HO -H H -OH H -OH CH OH D, hexose, ketose, 3 D, pentose, aldose 4 OL, hexose, ketose, 3 L, pentose, aldose, 4
Question 13 (4 points) What is the common name of the compound listed below? N,N-dimethyl-N-sec-butane dimethylisobutylamine ON. N-dimethyl-2-butanamine O sec-butyldimethylamine Question 14 (4 points) Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CH,OH H -OH H -OH CH OH OL, pentose, ketose, 2 OD pentose, ketose, 2 OD. tetrose, aldose 3 OL. tetrose, aldose, 3
Question 5 (4 points) What is the major product of the following reaction? 1. NaOET Eto ΟΕΙ 2. Hot O OE EIO OH OE O O- EIO OH OEt OE EtO 애 OEt Question 6 (4 points) Friedel-Crafts acylation reactions cannot be performed on benzoic acid because: The carboxylic acid group gets acylated instead of the aromatic ring. The carboxylic acid group is moderately deactivating preventing any substitution on the aromatic ring. The carboxylic acid group attacks the Lewis acid...
help asap Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated. The amino group is strongly activating and multiple substitutions occur on the aromatic ring. The amino group is strongly deactivating preventing any substitution on the aromatic ring. The amino group gets acylated instead of the aromatic ring. Which of the following produces no reaction? -O'Na+ + H2O CH3 Li+...
2. Draw Fischer projections of the open chain tautomer of each of the monosaccharides shown below, and indicate whether the compound is: i. an aldose or a ketose; ii. a D- or an L-sugar; iii. a triose, tetrose, pentose or hexose OH OH HO HO HO OH OH HO OH OH HO H OH 3. Draw Fischer projections of L-arabinose, D-fucose, and L-mannoheptulose given the structures below OH CHO CHO HOH HOH HOHH H-OH HOH H OH H OH OH...
CHO 1. NH2OH 2. Ac2o 3. CH,O CHO OH H- HO H HO H HCN H OH OH H- OH H- -OH H- CH2OH CH2OH The Wohl degradation is a series of reactions that shorten an aldose chain by one carbon, it is almost the exact opposite of the Kiliani In this reaction the aldose aldehyde carbonyl group is converted into a nitrile. The resulting cyanohydrin loses HCN under basic cone Conversion of the aldehyde to a nitrile is accomplished...