Question

1. predict the products KOH, H20 Ph H heat a. (21.4) 1. LDA (strong bulky base) O H b . 2. then heat Н. (21.4) C. NaOH H2O int of H H cold (21.3) 1. LDA Vio 2. e. 3. mild acid for neutralization (21.5)
I'll be glad if you solve all of them, but number 1(a-e) is must to do. Please solve all of them. Thank you so much

Answer 1

Answers 0 KOH H₂O Ph H + Ph heat Product mechanism os H &proto & Ph Ph H2024 Serge H-024 90-H ph Ph KOH Product

b ) 1) LDA (s tong bulky म base •H 2) H then heat Product Mechanism + LDA I He LON + 06 И Hogh H H HO НО: M Product

c) OH oa N40M 1,0 И cold lt Product Due to cold reaction condition reaction stops at 8 hydouxy aldol product mechanism NH H MO OH Ho Ho H J H₂O OH Н. product 0 er i 1) LDA + HOT 3) mild acid for neutralization Products mechanism que t® Li ( P.7.0.)

Product н КІ, (mild acid но

6) Reaction o Ost we will have product from reaction le ciel (21.3) we will write that reaction. Naol >04 + no H (-HO H michael product of that reaction Reaction we will doaw the claisen condensation product of ethyl acetate. Etoma -CH-CH₂ 2 CHg Etom (4- (Ha 2 И 3 Product

Reaction by CH-CM + Ma매 예 여 0 - (HH + H 이 내 Ho에 아내 -CH 는 Keto-enol 3 tautomerisation 아H-H Product