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What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0140...
Question 22 of 33 What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0490 V and n = 2? (F = 96,500 J/(V.mol), R = 8.314 J/(mol·K))
1) Calculate the cell potential, E°cell, for the following electrochemical reaction. Cu(s) + I2(g) → Cu+2(aq) + 2I-1(aq) E = ? a.-0.87 V b.-0.19 V c.0.19 V d.0.87 V 2) Calculate the equilibrium constant (Keq) for the following reaction at 25 °C? (Faraday's Constant = 96,500 J / V · mol) & (R = 8.314 J / mol · K) 2Fe+3(aq) + Sn+2(aq) → 2Fe+2(aq) + Sn+4(aq) K = ? a. 4.04 x 107 b. 3.44 x 1018 c. 4.48...
An electrochemical cell is set up at 25°C based on the overall reaction represented by the balanced equation shown below. The cell initially has [Cr3+] = [Cu2+] and E°cell = +1.08 V. $$3Cu2+(aq)+2Cr(s)3Cu(s)+2Cr3+(aq) How many moles of electrons are transferred per reaction cycle (i.e., for 1 cycle of the equation as written)? 6 Part 3 (1 point) Using the relationship given in part 1, calculate Ecell if [Cu2+] = 1.453 M and [Cr3+] = 0.00176 M, assuming that the temperature remains...
Pt1 An electrochemical cell is set up at 25°C based on the overall reaction represented by the balanced equation shown below. The cell initially has [Cr3+] = [Cu2+] and E°cell = +1.08 V. 3Cu2+(aq)+2Cr(s)harpoon_left.pngharpoon_rigth.png3Cu(s)+2Cr3+(aq) -Using the relationship given in part 1, calculate Ecell if [Cu2+] = 1.453 M and [Cr3+] = 0.00209 M, assuming that the temperature remains at 25°C. Give your answer to two places after the decimal. (R = 8.314 J/mol·K and F = 9.65 × 104 C/mol...
The equilibrium constant, K, for a redox reaction is related to the standard potential, E∘, by the equation lnK=nFE∘RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e−) , R (the gas constant) is equal to 8.314 J/(mol⋅K) , and T is the Kelvin temperature. Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.51×10−3.
12. Considering the following electrochemical cell carried out at 25°C and using only the information in the table below: MnO2 (s) Cu (s)4 H (a) Mn2 (a) Cu2 (aq)2 H2O (0) Substance AH (kJ/mol) 0.00 219.4 0.00 285.8 64.9 520.0 AS (J/mol Cu (s) 33.2 78.8 0.00 70.0 98.0 53.1 H2O Cu (aq) MnO2 (s) a) If this system were at equilibrium, in what direction would the reaction go to re-attain its state of equilibrium if the temperature were incre...
When the following reaction is balanced under basic conditions, what is the ratio of the coefficients of Mn(OH)2(s) to MnO4--(aq)? Mn(OH)2(s) + MnO4 (aq) + MnO42-(aq) (A) 3:1 (B) 1:3 (C) 1:4 (D) 1:5 What is the standard reduction potential for the reduction of permanganate ion to managanese dioxide in acidic solution? Half-Reaction E. V MnO4 (aq) + 8 H(aq) + 5 € → Mn²+ (aq) + +1.51 4 H2O(1) MnO2(s) + 4 H (aq) + 2 e → Mn2+(aq)...
The equilibrium constant, K. for a redox reaction is related to the standard potential, E, by the equation Fe(s) + Ni+ (aq) +Fe?+ (aq) + NI(s) FE In K = Express your answer numerically. View Available Hints) where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mole). R (the gas constant) is equal to 8.314 J/(mol-K). and T is the Kelvin temperature. ΟΙ ΑΣΦ h ? KK- Submit Previous Answers *...
What is the expected standard cell potential for the following unbalanced reaction under basic conditions? MnO4-(aq) + Fe+2(aq) ⟶ Fe+3 (aq) + MnO2(s) Given: Fe3+ + e− ⟶ Fe2+ E1/2= 0.771 MnO4−+ 2 H2O + 3e− ⟶ MnO2 + 4OH− E1/2 = 0.558 A. -0.213 V B. +0.213 V C. -1.329 V D. +1.329 V E. None of the above
Balance the following REDOX reaction in basic solution: I2(s) + MnO2(s) ---> I-(aq) + MnO4-(aq) (E0 = -0.060 V) The equilibrium constant for this reaction at 25 degrees C is: 8.30 X 10-7 b. 1.38 X 10-7 c. 0.36 d. 8.30 X 107