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Question 3 30 pts Given the following predictive results: Sample ID (id) Predicted Probability (prob) Sample Label (label) 1

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Sample TD Predicted Probability Sample Label Сprob) -- Уpred y ŷ (0.6) 1 0.9 2 0-8 3 0-3 0 0.6 0 4 5 (0.9>=0.6) (0.8>=0,6) (0True Positive :- Both values are 1 (y and ŷ False Negative Y is I and ŷ is 0. Consider Y and TPR = TP=2 (Sample IDs 1 and 6)False positive: Y is o and 9 is 1 True Negative : Both Y and ŷ are o. FPR = 2+2 FP=2 (sample IDs & and 4) TN = 2 ( Sample IDsTh=0.6 (0.3, 0.5) 2 TPR = it = 0.3 FPR= =0.5 142 2+2 Th=008 (0-2,0.2) 0.2 FPR = TPR = 1+3 1+3 Th= 1 (0,0) 0 TPR = 2=0 FPR =0Summary: We have seen how to calculate TPR and FPR. Considered some threshold values to calculate TPR and FPR and noted down every pair of (TPR, FPR). Represented FPR on X-axis and TPR on Y-axis

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