Sample ID | Predicted Value | Sample Label |
1 | .9 | 0 |
2 | .7 | 1 |
3 | .5 | 1 |
4 | .8 | 1 |
5 | .4 | 0 |
6 | .3 | 1 |
(a) Using 0.5 as a cutoff, namely >=0.5 then predict the sample as 1, and 0 otherwise. Please compute true positive rate and the false positive rate.
(b) please compute its AUC manually https://www.coursehero.com/file/27125786/Fall-16-Quiz-5pdf/ This study re
Sample ID | Predicted Value | Predicted Label(threshold >=0.5) | Sample Label |
1 | .9 | 1 | 0 |
2 | .7 | 1 | 1 |
3 | .5 | 1 | 1 |
4 | .8 | 1 | 1 |
5 | .4 | 0 | 0 |
6 | .3 | 0 | 1 |
(a)
True positive Rate: ration of correct positive label predicted and total positive label
here correct positive label predicted are of sample ID: 2,3 ,4
thus TP = 3
and positive label are of sample: 2, 3 ,4 6
and P = 4
Then
False positive Rate: ration of incorrect negative label predicted as positive and total negative label
here incorrect negative label predicted as positive are of sample ID: 1
thus FP = 1
and negative label are of sample: 1,5
and N = 2
Then
Question 3 30 pts Given the following predictive results: Sample ID (id) Predicted Probability (prob) Sample Label (label) 1 0.9 1 0.8 0 N 3 0.3 1 4 0.6 o 5 0.4 o 6 0.7 1 7 0.1 0 8 0.2 1 (10 Pts.). Suppose 0.6 is a cutoff, then the sample is predicted to be 1 if its probability >=0.6, and o otherwise. Please compute tpr and fpr. . (20 Pts.). Please compute its AUC manually. You need to...
DATA 2 ID X1 X2 X3 Y A 0 2 4 9 B 1 0 8 10 C 0 1 0 5 D 1 1 0 1 E 0 0 8 10 CORRELATION MATRIX Y X1 X2 X3 Y 1 ? -0.304 +0.889 X1 ? 1 -0.327 0 X2 -0.304 -0.327 1 -0.598 X3 +0.889 0 -0.598 1 1. What is the mean squared error of the full model? (Correct answer is 4, please show me how to get there)...
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